Model 2 Simplification based on square & square root Practice Questions Answers Test with Solutions & More Shortcuts
simplification PRACTICE TEST [4 - EXERCISES]
Model 1 Simplification using VBODMAS
Model 2 Simplification based on square & square root
Model 3 Simplification based on cube & cube root
Model 4 Simplification with continued fraction
Question : 11
The value of $√{5+ √{11 + √{19 + √{29 + √{49}}}}}$ is
a) 9
b) 7
c) 3
d) 5
Answer »Answer: (c)
$√{5+ √{11 + √{19 + √{29 + √{49}}}}}$
$√{5+ √{11 + √{19 + √{29 + 7}}}}$
$√{5+ √{11 + √{19 + 6}}}$
$√{5+ √{11 + √{25}}}$
$√{5+ √{11 + 5}}$
$√{5+ 4} = √9$ = 3
Question : 12 [SSC FCI Ass Grade-III 2013]
The value of $(3 + √{8}) + 1/{3 - √{8}} - (6 + 4√{2})$ is
a) 1
b) $√2$
c) 8
d) 0
Answer »Answer: (d)
${1/{3 - √8}} = {3 + √8}/{(3 - √8)(3 + √8)}$
(Rationalising the denominator)
= ${3 + √8}/{9 - 8} = 3 + √8$
Expression
= $3 + √{8} + 3 + √{8} - 6 - 4√{2}$
= $6 + 2√{8} - 6 - 4√{2} = 2√{8} - 4√{2}$
= $2 × 2√{2} - 4√{2} = 0$
Question : 13 [SSC CGL Prelim 1999]
Assume that $√{13}$ = 3.605 (approximately) $√{130}$ = 11.40 (approximately) Find the value of : $√{1.3} + √{1300} + √0.013$
a) 36.304
b) 37.304
c) 36.164
d) 37.164
Answer »Answer: (b)
$√{1.3} + √{1300} + √0.013$
= $√{{130}/{100}} +10√{13} + √{{130}/{10000}}$
= $1/10√{130} + 10√{13} + 1/100√{130}$
= ${11.40}/10 + 3.605 × 10 + {11.40}/100$
= 1.140 + 36.05 + 0.1140
= 37.304
Question : 14 [SSC CPO S.I.2008]
$√{{0.081 × 0.484}/{0.0064 × 6.25}}$ is equal to
a) 0.9
b) 99
c) 9
d) 0.99
Answer »Answer: (d)
Expression
=$√{{0.081 × 0.484}/{0.0064 × 6.25}}$
= $√{{81 × 484}/{64 × 625}} = {9 × 22}/{8 × 25} = 0.99$
Question : 15 [SSC CGL Prelim 2002]
The square root of ${0.342 × 0.684}/{0.000342 × 0.000171}$ is :
a) 2500
b) 2000
c) 250
d) 4000
Answer »Answer: (b)
$√{{0.342 × 0.684}/{0.000342 × 0.000171}}$
= $√{{342 × 684 × {10}^6}/{342 × 171}}$
= $√{4 × {10}^6} = 2 × {10}^3$ = 2000
IMPORTANT quantitative aptitude EXERCISES
Model 2 Simplification based on square & square root Shortcuts »
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